Department of Mathematics, K.T.H.M. College, Nashik

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Registered: 23-07-2015

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Algebra -Precalculus

The Value of $$100\left[\frac{1}{(1)(2)}+\frac{1}{(2)(3)}+ \frac{1}{(3)(4)}+\ldots+\frac{1}{(99)(100)}\right]$$

A)is 99;
B)lies between 50 and 98;
C) is 100;
D)is different from valuse specified in the forgoing statments.
[Hint:use $$\frac{1}{n(n+1)}=\frac{1}{n} -\frac{1}{n+1}$$
Ans is (A) is 99.